Three triangles have sides of lengths 3, 4, and 5. Their respective perimeters are 6, 8 and 10. The triangles are similar to each other. True or false

'll tell you where the problem lies - it is IMPOSSIBLE to form triangles like this.

If the perimeter of the smallest triangle is 6 and one side is 3, then the sum of the other two sides can only be 6 - 3 = 3

One property to enable you to form a triangle is that NO ONE SIDE can be greater or equal to the sum of the other two sides. In the smallest triangle 1 side of length 3 equals the other two sides.

In the middle triangle one side of length "4" equals the sum of the other two sides and

In the large triangle one side of length "5" equals the other two sides.

Therefore when I say "triangle" above I am not actually correct because it is IMPOSSIBLE to form triangles with those dimensions of 1 side and with those perimeters

table 3 represents a direct variation function. : )

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.