Find two numbers if their Least Common Multiple, LCM is 100 and their Highest Common Factor, HCF is 5. Give two possible pairs of answers. ​

Step-by-step explanation:

Let H = HCF(A,B) and L = LCM(A,B)

Then A*B = L*H

Here L*H = 100*5 = 500

Also H <= A ,B <= L

So we need to find all A*B = 500, satisfying the above condition. This can be done using prime factorisation of 500.

Here 500 = 2^2 * 5^3

so possible values of A and B are

1 , 500

2, 250

4, 125

5,100

10,50

20,25

(assuming order doesn’t matter.)

so pairs satisfying given condition are → (20,25) and (100,5)

You can write a computer program in language of your choice to do it for other bigger numbers.

i think it would be 43 movies that would have to be watched.

step-by-step explanation:

think about it. for the second plan, every month is 8 dollars. 8 x 12= 96. so thats the number for the second plan. now for the first plan, its annual meaning you have to pay 10 dollars every year. so now you have to get an equivalent amount of 86 since 96-10=86. 86 divided by 2 since every movie costs 2$ then you would have to watch 43 movies a year to get the same as the second plan. i really hoped this . have a wonderful day as well!