Soup can be packaged in two different containers: a box and a cylinder. The dimensions of the box are 7.5 cm by 4.7 cm by 14.5 cm. The cylinder has a radius of 3.3 cm and a height of 10 cm. Determine which container uses less material to make and find out which container holds more soup.

Cylinder uses less material to make.

Box holds more soup then cylinder.

Step-by-step explanation:

Total surface area of cuboidal box =2(lw+wh+lh), l= length, w=width, h=height

Total surface area of cylinder =  where r= radius and h is height.

Given , Dimension of box : 7.5 cm by 4.7 cm by 14.5 cm

Dimension of cylinder : radius of 3.3 cm and a height of 10 cm.

Total surface area of box =2((7.5)(4.7)+(4.7)(14.5)+(7.5)(147.5)) sq. cm

= 2(1209.65)

=2419.3 sq. cm

Total surface area of cylinder =

[π=3.14]

(Total surface area of cylinder)<(Total surface area of box )

So, cylinder uses less material to make.

Volume of box = l x w x h

= (7.5)(4.7)(14.5) =511.13 cubic cm

Volume of cylinder =

= 341.946 cubic cm

As (Volume of box) > (Volume of cylinder )

So, Box holds more soup then cylinder.

the y will be in still but your answer will be y x 3

step-by-step explanation:

jk: )

sorry, i'm new here and i'm just trying to figure this out. try quizlet. rate 5* you!