The remainder when 2x^2-x-5 divided by (x-3) is

10

Step-by-step explanation:

2x^2-x-5= 2x^2-6x + 5x -15 +10= 2x(x-3) +5(x-3) + 10= (2x+5)(x-3) + 10

(2x^2-x-5)/(x-3)= 2x+5 + 10/(x-3)

So the remainder is 10

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

2.56 is the width of the garden

step-by-step explanation: