An isosceles triangle has a base whose length is 14 centimeters and whose base angles each measure 68 degrees. Which of the following is closest to the area of
the isosceles triangle in square centimeters?
(1)242
(2) 121
(3)98
(4)196

Area of the triangle is 121 cm²

Step-by-step explanation:

To solve this, we will follow the steps below;

We will first find the height of the triangle, from the diagram below:

opposite = h where h is the height of the triangle

adjacent = 7

Ф=68°

Using trig.ratio

tan Ф = opposite/adjacent

tan 68° = h/7

h = 7 tan 68° = 17.33

height of the triangle =17.33 cm

From the question, base(b) = 14 cm

Area of a triangle = 1/2 × b × h

                             =1/2×14×17.33

                             =121.31

                            ≈ 121 cm²

Area of the triangle is 121 cm²