Physics, 10.01.2020 02:31 chem1014

Aparallel-plate capacitor has plates of area a. the plates are initially separated by a distance d, but this distance can be varied. the capacitor is connected to a battery.

a) what should the plate separation be if you want to halve the capacitance.

b)what should the plate separation be if you want to halve the capacitance.

c)what should the plate separation be if you want to halve the charge stored?

d) what should the plate separation be if you want to halve the charge stored?

e)what should the plate separation be if you want to halve the energy stored?

f)what should the plate separation be if you want to halve the energy stored?

g)what should the plate separation be if you want to halve the energy density?

Answers: 2

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Answer from: masonprice

a) In a parallel plate capacitor the capacitance is

$C = \frac{Q}{V} = \epsilon_0\frac{A}{d}$

So, in order to halve the capacitance the plate separation should be twice the original distance.

b) Same question as (a).

c) According to the above equations, the charge stored in a capacitor is directly proportional to the plate separation.

$\frac{Q}{V} = \frac{A}{d}$

In order to halve the charge stored the plate separation should be half the original distance.

d) Same question as (c).

e) The energy stored in a capacitor is

$U = \frac{1}{2}CV^2 = \frac{1}{2}\epsilon_0\frac{A}{d}(Ed)^2 = \frac{1}{2}\epsilon_0AE^2d$

In order to halve the energy stored in the capacitor, the plate separation should be twice the original distance.

f) Same question as (e).

g) The energy density is given by the following equation

$u = \frac{\frac{1}{2}CV^2}{Ad} = \frac{\frac{1}{2}\epsilon_0\frac{A}{d}(E^2d^2)}{Ad} = \frac{1}{2}\epsilon_0E^2.$

As it turns out, the energy density is independent from the geometric factors. This makes sense, because the electric field in a parallel field capacitor is independent from the distance.

Answer from: Quest

Edit the post so i can see the letters for each answer, and increase the points required so i'd be able to answer it.

Answer from: Quest

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

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Aparallel-plate capacitor has plates of area a. the plates are initially separated by a distance d,...