The supreme choice pizza at Pizza Paradise contains 2 different meats and 4 different vegetables. The customer can select any one of 5 types of crust. If there are 4 meats and 9 vegetables to choose from, how many different supreme choice pizzas can be made?

756

Step-by-step explanation:

This is a combination problem. Combination has to do with selection.

If we are to select r objects out of a oiil of n objects, this can be done in nCr number of ways as shown;

nCr = n!/(n-r)!r!

From the question, there are 4 meats and 9 vegetables to choose from. If the customer is to select 2 different meats and 4 different vegetables from the available ones, this can be done as shown

4C2 (selection of 2 different meats from 4meats) and 9C4(selection of 4 different vegetables from 9 total vegetables)

The total number of ways this can be done is 4C2 × 9C4

= 4!/(4-2)!2! × 9!/(9-4)!4!

= 4!/2!2! × 9!/5!4!

= 4×3×2!/2!×2 × 9×8×7×6×5!/5!×4×3×2

= 6 × 9×7×2

= 756ways

This means 756 different supreme choice pizzas can be made.

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation:

3000000000000000000000