Solve: A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. Write a quadratic function equation that describes the height h at time t.
Write this polynomial in standard form. ax2 + bx + c a≠ 0
Find the maximum height.
Be sure to answer the question using the correct units.
Write a quadratic function equation that describes the height h at time t.

h\left(t\right)=-16t^2+v_0t+h_0
h(t)=−16t
2
+v
0

t+h
0

5t² - 16t + h =0

Step-by-step explanation:

During upward projection the final velocity is zero, and the gravitational acceleration is -10 m/s² (against the gravity).

Therefore; using the equation;

S = 1/2gt² + ut

Where s is the height h, g is gravitational acceleration, and t is the time and u is the initial velocity u, is 16 ft/s.

Thus; h= 1/2(-10)t² + 16t

We get; h = -5t² + 16t

Therefore; the quadratic equation is 5t² - 16t + h =0

Plz, mark me brainlest!!

c

-by-step explanation:

it would be c

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.