2x + 6y= 8
4x + 12y = 16

x=0 , y=0

Step-by-step explanation:

2x +6y= 8 eqn 1

4x +12y= 16eqn2

we multiply eqn 1 by 2.. because we want at least one variable to have the same coefficient so we can simply.

2x +6y =8... ×2

will give you 4x +12y = 16eqn 3

so now we subtract eqn 2 from eqn 3

4x + 12y= 16

- 4x + 12y = 16

0 + 0 = 0

therefore x = 0 and y= 0

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.