When a baseball is thrown upward, its height is a function of time. If this function is given by formula h(t)=−16t^2+24t+5, what is the maximal height it reaches?
Nevermind I got it

the maximal height is 14.75 units of distance.

Step-by-step explanation:

We want to find the maximum height of the function

h(t) = -16*t^2 + 24*t + 5

In order to find the maximum, we need to find the value of t where the derivate of h(t) is equal to zero, then we evaluate our original function in that time.

The derivate of h(t) (or the vertical velocity) is:

h'(t) = 2*(-16)*t + 24 = -32*t + 24

we want to find the value of such:

0 = -32*t +24

32*t = 24

t = 24/32 = 0.75

Now we evaluate our height function in that value.

h(0.75) = -16*0.75^2 + 25*0.75 + 5 = 14.75 units

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

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or  

y

≥

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.

(

−

∞

,

−

2

]

∪

[

0

,

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{

y

|

y

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step-by-step explanation:

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.