Mathematics, 18.09.2020 21:01 lurinha8

40/64 as equivalent fraction

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It seems like they're both divisible by 8, so let's do that.
40/64 = 5/8
There is no way to divide 5/8 while keeping the whole numbers.
Therefore, 40/64 has an equivalent fraction of 5/8.

However, that is the simplest equivalent fraction. Other ones can include:
40/64 = 80/128 (multiply both sides by 2)
40/64 = 20/32 (divide both sides by 2)

As long as you only multiplied or divided both the numerator and the denominator with same values, it is considered as an equivalent fraction as the fraction before

Answer from: Glamis856

Some equivalent factions are 10/16
You get this by doing 40÷4=10 and 64÷4= 16.
So you get 10/16
~JZ

Answer from: Quest

there are lots of ways. pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula. the area is half the sum of the cross products of the sides.

a(-2,6) -2(2)-6(-5) = 26

b(-5,2) -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3) 4(3) - (-3)(5) = 27

e(5,3) 5(3) - 3(1) = 12

f(1,3) 1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 + 18 + 27 + 12 + 12) = 57

that checks!

Find the area of the following shape. you must show all work to receive credit. need asap timed tes

Answer from: Quest

b. the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

f(-2) = -3f(1) = 6 . . . estimated from f(x) = (x+2)^2-3, which matches points on the graph (-1,-2) and (0, 1)

so the change in y-value for function f is (6 )) = 9.

the table tells us

g(-2) = 1g(1) = 31

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).