Find the equation of the circle with center at (-1, 3) and radius of 4.

(x+1  )^2+(y−3)^2= 16

Step-by-step explanation:

We can write the equation of a circle as

(x−h)^2+(y−k)^2=r^2

Where (h,k) is the center and r is the radius

(x− -1  )^2+(y−3)^2= 4^2

(x+1  )^2+(y−3)^2= 4^2

(x+1  )^2+(y−3)^2= 16

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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