Given an int variable n that has already been declared and initialized to a positive value, and another int variable j that has already been declared, use a for loop to print a single line consisting of n asterisks. thus if n contains 5, five asterisks will be printed. use no variables other than n and j

#include<iostream>

using namespace std;

//main function

int main(){

   //initialize the variables

   int n = 5;

   int j=1;

   // for loop

   for(;j<=n;j++){

       cout<<"*";  //print the '*'

   }

}

Explanation:

Create the main function and declare the variable n with the value 5 and initialize the variable j with zero.

take a for loop for executing the statement again and again until a condition is not false.

Syntax for loop:

for(initialize; condition; increment/decrement)

{

 statement;

}  

we can initialize the variable outside as well but the semicolon always present in the loop otherwise compiler gives the error.

for example:

int i=0;

for(; i<4; i++){

  statement;

}

The condition put in the original code is j <= n and n has the value 5. so, the loop executes 5 times and inside the loop, write the print statement for print the character '*'.

i think so.

by: nicholas