A circle with the equation (x + 4)2 + (y + 2)2 = 36 is reflected over the line x = 1. What is the equation of the image? (x + 4)2 + (y - 2)2 = 36 (x - 6)2 + (y + 2)2 = 36 (x + 6)2 + (y - 2)2 = 36 (x - 4)2 + (y + 2)2 = 36

B

Step-by-step explanation:

Currently, the graph looks like the attachment.

The centre of this circle is at (-4, -2), but when we flip it over the line x = 1 (the blue line on the picture), the centre will become ((1- -4) + 1, -2) = (6, -2).

Look for the equation that matches this center. We want the center (h, k) to be (6, -2), so our equation should look something like:

The answer is B.

(x - 6)² + (y + 2)² = 36

Step-by-step explanation:

Centre before reflection: (-4,-2)

Centre after reflection:

(-4+5+5,-2) = (6,-2)

(x - 6)² + (y + 2)² = 36

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.