1) Let X represent the number of tires with low air pressure on a randomly chosen car. The probability of distribution of X is as follows:
X 0 1 2 3 4
P(X) 0.1 0.2 0.4 0.2 0,1

a) Find the probability of 1 tire with low air pressure P (1) =

b) Find the probability of more than 2 tires having low air pressure P (more than 2) =

c) P (all 4 tires) =

d) Compute the expected number of tires with low air pressure.

e) Compute the standard deviation for the number of tires with low air pressure.

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

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step-by-step explanation:

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