Find the sum of – 1676 + (-1669) + (-1662) + ... +(-115) + (-108).

Step-by-step explanation:

This is arithmetic series

first term (a) = -1976

common difference = 2nd term - 1st term

                                = (-1669) - (-1676)

                              =(-1669) + 1676

                           d = 7

nth term = a + (n-1)d

(-1676)   + (n-1) 7 = (-108)

(-1676) + 7n - 7 = (-108)

-1683 + 7n = -108

7n = -108 + 1683

7n =   1575

n = 1575/7

n = 225

last term (l) = -108

sum = n/2(a + l)

be more specific

step-by-step explanation:

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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