A circle is shown. Secants E C and A C intersect at point C outside of the circle. Secant E C intersects the circle at point D. Secant A C intersects the circle at point B. The length of E D is 14, the length of D C is x + 1, the length of A B is 21, and the length of B C is x. What is the value of x?

x=3

Step-by-step explanation:

The diagram is attached.

To solve this we apply the theorem of intersecting secants.

By this theorem, in the diagram:

(x+1) X (14+x+1) = x X (21+x)

(x+1)(15+x)=x(21+x)

Expand the brackets

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

s

step-by-step explanation: