The nitrogen oxide (NO) molecule has a bond length of 140 pm. Calculate the dipole moment, in Debyes, that results if the charges on N and O were 2 and 2-, respectively. (Include the formula for the calculation in your solution)

Explanation:

Dipole moment = charge x separation of charges

= (2 x 1.6 x 10⁻¹⁹ ) x ( 140 x 10⁻¹² ) coulomb-metre

= 448 x 10⁻³¹coulomb-metre

1 debye = 3.33 x 10⁻³⁰coulomb-metre

Dipole moment in debye =  448 x10⁻³¹ / 3.33 x 10⁻³⁰debye

= 448 x10⁻³¹ / 33.3 x 10⁻³¹

= 13.45 debye

=

the answer is either b or c

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong