Eight percent of all college graduates hired by companies stay with the same company for more than five years. The probability that in a random sample of 12 such college graduates hired recently by companies, exactly two will stay with the same company for more than five years is

Probabilities are used to determine the chances of an event.

The probability that exactly two stays more than 5 years is 0.1835

The given parameters are:

---- sample

--- selected

--- sample proportion

So, the probability that exactly two stays more than 5 years is calculated using the following binomial probability:

So, we have:

Solve 12C2 using a calculator

Hence, the probability that exactly two stays more than 5 years is 0.1835

Read more about probabilities at:

link

0.1835

Step-by-step explanation:

This question can be solved by way of binomial distribution.

Let’s have the probability of success as p which is the probability that they stay with the company for more than five years;

p = 8/100 = 0.08

probability of failure, meaning not staying is q = 1-p = 1-0.08 = 0.92

Now let’s write the expression for the binomial distribution. That would be;

probability = 12C2 * 0.08^2 * 0.92^10

= 0.1835

your answer is b ^w^ hope i

30 people weigh 160 pounds or more