A balloon has a volume of 0.8.0 m3. As it rises in the earth s atmosphere, its volume expands. What will be its new volume if its original temperature and pressure are 20 C and 1.0 atm, and its final temperature and pressure are -40 C and 0.10 atm

6.36 m³

Explanation:

Using the general gas law

P₁V₁/T₁ = P₂V₂/T₂

Given that P₁ = 1.0 atm, V₁ = 0.8 m³ and T₁ = 20 °C = 273 + 20 = 293 K and P₂ = 0.10 atm, V₂ = unknown and T₂ = -40 °C = 273 + (-40) = 273 - 40 = 233 K

So, V₂ = P₁V₁T₂/P₂T₁

Substituting the values of the variables into the equation, we have

V₂ = 1.0 atm × 0.8 m³ × 233 K/0.10 atm × 293 K

V₂ = 186.4 atm-K-m³/29.3 atm-K

V₂ = 6.36 m³

So, the new volume of the balloon is 6.36 m³.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

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enthalpy change for the reaction between the given volumes of the gases is :

the correct answer would be b) volume versus temperature, because they are also directly proportional.