What is f(5) if f(1) = 3.2 and f(x + 1) = Five-halves(f(x))?

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Step-by-step explanation:

i just answered the question. ed2020

Step-by-step explanation:

then f(2) = f(2-1) - 5 = f(1) - 5 = 2 - 5 = -3

thenf(3) = f(3-1) - 5 = f(2) - 5 = -3 - 5 = -8

then f(4) = f(4-1) - 5 = f(3) - 5 = -8 - 5 = -13

then f(5) = f(5-1) - 5 = f(4) - 5 = -13 -5 = -18

then f(6) = f(6-1) - 5 = f(5) - 5 = -18 -5 = -23

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)