Complete the following multiplication problems. a. 0.34 × 6 b. 0.11 × 4 c. 17 × 0.07 d. 28 × 0.003 e. 3.8 × 5 f. 5.931 × 7 g. 14.07 × 13 h. 3.005 × 32 i. 0.8 × 0.3 j. 0.45 × 0.05 k. 0.09 × 0.02 l. 0.074 × 0.08 m. 2.3 × 0.9 n. 7.25 × 0.3 o. 4.53 × .003 p. 53.67 × 0.056 q. 1.1 × 3.7 r. 3.76 × 18.9 s. 4.57 × 6.1 t. 24.13 × 1.48

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

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step-by-step explanation:

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