A pot full of water weighs 2 kg (the total combined weight of the pot and the water). If we spill out 20% of the water, the weight of the pot and water together is 88% of the original weight. What is the weight of the empty pot in kg. Express your answer as a common fraction in lowest terms.

the empty pot is 0.8 kg or 4/5 kg. just do the weight lost times five and you get the answer. (times five because 1/5th of the water was lost. so to get the original weight of the water you multiply by the divisor (5)). Then you subtracts 1.2 from 2 and your and is 0.8 or 4/5ths

i don't see any

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b