Find the equation of a line through the points (-10,-3) (5,-9)

y = 1.6x -17

Step-by-step explanation:

Point Slope Form:   y-y₁=m(x-x₁)

1. We will use this format to Find the equation of a line through the points (-10,-3) (5,-9)

2. Calculate the slope from 2 points

 m = y2 - y1 /   x2- x1

 m = -9 - (-3) /   5- (-10)

 m = -6/ 15

 m = 1.6

3. Substitute the slope for 'm' in the slope intercept form of the equation

y = mx +b

y = 1.6x +b

4. Substitute either point into the equation. You can use either (-10,-3) or (5,-9)

y = 1.6x +b

-9 = 1.6(5) + b

5. Solve for b, which is the y-intercept of the line

-9 = 1.6(5) + b

-9 = 8 + b

-9 = 8 + b

-17 = b

6. Substitute b, -17, into the equation from step 3

y = 1.6x +b

y = 1.6x -17

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq