Raul is building a house
on day 1, he uses 3 bags of cement
on each of the following 3 days, he uses 3 times the number of bags used the previous day
how many bags of cement does he use in the last 3 days?

117 bags

Step-by-step explanation:

First day number of bags used by Raul=  3 bags

  We have to calculate the number of bags next three following days

On second day, number of bags used by Raul= 3×3=9

similarly, on third day number of bags used by Raul= 9×3=27

similarly, on fourth day number of bags used by Raul= 27×3=81

 Hence, the total number of bags used by Raul= 9+27+81=117

Hence, the correct answer is 117

sorry, can't i suggest going to algebra.com

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet