Mathematics, 26.02.2020 04:32 jadenpmoore2008
An article presents results of a survey of adults with diabetes. The average body mass index (BMI) in a sample of 1551 men was 30.4, with a standard deviation of 0.6. The average BMI in a sample of 1920 women was 31.1 with a standard deviation of 0.2. Let μX represent the population mean BMI in women with diabetes and let μY represent the population mean BMI in men with diabetes. Find a 99% confidence interval for the difference μX−μY. Round the answers to three decimal places.
Answers: 3
is givenby (0.659; 0.741)
represent the sample mean for women
the sample size of women
standard deviation for women
represent the sample mean for men
the sample size of men
standard deviation for men
(1)
and 
, with that value we can find the quantile required for the interval in the normal standard distribution.
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An article presents results of a survey of adults with diabetes. The average body mass index (BMI) i...
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