Peter the optician sees 16 patients one Tuesday.4 are neither short nor long sighted, the total number of short sighted patients is 2 more than the total number of long sighted, how many patients can be short sighted, how many long sighted, and how many will require varifocal lenses

The number of short-sighted patients is 7

The number of long-sighted patients is 5

The number of patients requiring a varifocal lens is 4

Step-by-step explanation:

Stepwise solution-

Throughout the question, only 3 types of patients are mentioned. Hence, it would be safe to assume that he saw/sees these 3 types of patients on Tuesday.

As per the given details-

4 are neither short-sighted patients nor long-sighted patients. Then it means no of varifocal lens patients is 4.

Hence remaining total patients=16-4=12

As given, no of short-sighted patients is 2 more than the number of long-sighted patients.

Let us assume the number of long-sighted patients as “x”

Thus, the number of short-sighted patients would be “x+2”

x+(x+2)=12   (total remaining patients)

2x=10

x=5

Hence, No. of long-sighted outpatients = 5

            No. of short-sighted outpatients =7

c

step-by-step explanation:

c

step-by-step explanation:

for exempl this   system of equations   y = x - 3

                                                                y = 2x - 5

look   the line : y = x -3     ( red)

                            the line : y = 2x -5 ( bleus)