An index that is a standardized measure used in observing infants over time is approximately normal with a mean of 90 and a standard deviation of 12. Use StatCrunch to find the proportion of children have an index of at least 110.

The proportion of children that have an index of at least 110 is 0.0478.

Step-by-step explanation:

The given distribution has a mean of 90 and a standard deviation of 12.

Therefore mean, = 90 and standard deviation, = 12.

It is given to find the proportion of children having an index of at least 110.

We can take the variable to be analysed to be x = 110.

Therefore we have to find p(x < 110), which is left tailed.

Using the formula for z which is p( Z < ) we get p(Z < = 1.67).

So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)

Using the Z - table we can calculate p(Z < 1.67)  = 0.9522.

Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478

Therefore the proportion of children that have an index of at least 110 is 0.0478

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let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.