The imperfect test gives positive results (indicating drug use) for 80% of all interns who actually use drugs but also (incorrectly) for 3% of those who do not use drugs. Suppose that only 10% of all of these interns actually use drugs. If an intern is tested negative, what is the probability that he/she uses drugs

The probability that an uses drugs given that the result was negative is 0.0224.

Step-by-step explanation:

Let's denote the events as follows:

D = an intern uses drugs.

X = the test result was positive.

The information provided is:

Compute the probability that the test result of an intern is positive as follows:

The probability that the test result of an intern is positive is P (X) = 0.107.

Compute the probability that the result is negative given that he/she uses drugs as follows:

Compute the probability that an uses drugs given that the result was negative as follows:

Thus, the probability that an uses drugs given that the result was negative is 0.0224.

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

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step-by-step explanation: