Mathematics, 20.02.2020 19:56 destinee8863

Y = bˣ is equal to: log_{b}(y) = x 2^{x+1} = 9 log_{2}(9) = x+1 log_{2}(9)= \frac{log9}{log2} log_{2}(9)= \frac{0.954}{0.301} log_{2}(9)= 3.17 2^{x+1} = 9 log2^{x+1} = log9 (x+1)log2 = log9 (x+1)(0.301) = 0.954 (x+1) = 0.954/0.301 (x+1) = 3.17 x = 3.17 - 1 x = 2.17 The value of log_{2}(9)= 3.17 The value of x = 2.17

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Y = bˣ is equal to: log_{b}(y) = x 2^{x+1} = 9 log_{2}(9) = x+1 log_{2}(9)= \frac{log9}{log2} log_{2...