In the past, 75% or less of the tourists who visited Tacoma went to see the glass blowing museum. The management of the museum recently undertook an extensive promotional campaign. They are now interested in determining whether the promotional campaign actually increased the proportion of tourists visiting the museum. The correct set of hypotheses is

H0 : p ≤ 0.75   against Ha : p > 0.75

Step-by-step explanation:

We formulate our null and alter native hypotheses as

H0 : p ≤ 0.75   against Ha : p > 0.75

In the question the claim whether the promotional campaign actually increased the proportion of tourists visiting the museum is given which is formulated as alternative hypothesis.

So when we formulate the alternative hypothesis as Ha : p> 0.75 the null hypothesis is H0 p ≤ 0.75

Where p is the probability = 75% = 75/100 = 0.75

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: