writing the equation of
a
what is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (-5, 1)? check all
that apply.
y=-2x-1
2x + 5y = -5
y=-2x-3
2x + 5y = -15
1= -2.(x + 5)

2x + 5y = -5

Step-by-step explanation:

Two lines are said to be parallel if they have the same slope.

The equation of the line given :

2x + 5y = 10

To find the slope , we will write it in the form y = mx + c , where m is the slope and c is the y - intercept.

2x + 5y = 10

5y = -2x + 10

y = -2/5x + 10/5

y = -2/5x + 2

This means that the slope is -2/5 ,the line that is parallel to this line will also have a slope of -2/5.

using the formula:

= m ( ) to find the equation of the line , we have

y - 1 = -2/5(x -{-5})

y - 1 = -2/5 ( x + 5 )

5y - 5 = -2 ( x + 5 )

5y - 5 = -2x - 10

5y + 2x = -10 + 5

therefore :

2x + 5y = -5 is the equation of the line that is parallel to 2x + 5y = 10

2x + 5y = -5

Step-by-step explanation:please see attachment for explanation

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

answer:  

123455421

step-by-step explanation: easy