There are 8 brooms and 6 mops in a janitor's closet. what is the ratio of the number of mops to the total number of brooms and mops? . a: 4/3 . b: 3/7 . c: 7/3. d: 3/4

B.

Step-by-step explanation:

We are given that in a Janitor's closet

Number of brooms=8

Number of mops=6

We have to find the ratio of the number of mops to the total number of brooms and mops.

Total number of brooms and mops=8+6=14

Ratio of number of mops to the total number of broom and mops=6:14

Ratio of number of mops to the total number of broom and mops=

Ratio of number of mops to the total number of broom and mops=

Hence, the ratio of number of mops to the total number of broom and mops=

  q

step-by-step explanation:

each line from a vertex to the midpoint of the opposite side is called a median. the point where the medians intersect, point q, is the centroid.

the centroid of δabc is point q.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}