Suppose that there are two types of tickets to a show: advance and same-day. the combined cost of one advance ticket and one same-day ticket is $75. for one performance, 20 advance tickets and 35 same-day tickets were sold. the total amount paid for the tickets was $2100. what was the price of each kind of ticket?

The answer to your question is Advance = $35 and same-day = $40

Step-by-step explanation:

Advanced = a

Same-day = s

Equations

                       a +     s  = 75               (I)

                  20a + 35s = 2100             (II)

Process

1.- Solve the equations by elimination.

Multiply equation I by -20

                     -20a - 20s = -1500

                      20a + 35s = 2100

Simplify

                        0   + 15s = 600

Solve for s                  s = 600/15

                                    s = $ 40        

Substitute "s" in equation I to find "a"

                       a   +   40  = 75

Solve for a

                       a    = 75  - 40

                       a = 35

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

yes the data was not prsented

step-by-step explanation: