Question 3
2 pts
a plane takes about 4.5 hours to fly you 1800 miles from chicago to sacramento. at the
same time, another plane flies from sacramento to chicago. this plane travels with the
same average airspeed, but the flight to chicago takes 3.75 hours. find the average air-
speed of the planes. find the average wind-speed.
average air-speed:
mi/h
average wind-speed:
mi/h
no new data to save. last checked at 10: 06pm
submit

average air speed of plane=180mph

average wind speed=40mph

Step-by-step explanation:

let y=average air speed of the plane

let a=average wind speed

(y-a)=speed of plane, Chicago to Sacramento

(y+a)=speed of plane, Sacramento to Chicago

distance=travel time×speed

4.5 (y-a)=1800

3.75 (y+a)=1800

4.5y-4.5a=1800

3.75y+3.75a=1800

16.875y-16.875a=6750

16.875y+16.875a=8100

then add it

33.75y=14850

y=440

4.5a=4.5y-1800

4.5a=180

a=40

average air speed plane =180mph

average wind speed=40mph.

answer: two five pound bags one two pound

step-by-step explanation:

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."