Aused car dealer sold two cars for $1980 each. on the first car he made a 10 percent profit. on the second car he took a loss of 10 percent. taken together, did he profit or lose on the deals?

he neither made profit nor loss on both deals

Step-by-step explanation:

The cost of the first car sold by the car dealer is $1980. On the first car he made a 10 percent profit. This means that the profit made on the first car would be

10/100 × 1980 = 0.1 × 1980 = $198

Amount for which he sold the first car would be

1980 + 198 = $2178

The cost of the second car sold by the car dealer is $1980. On the second car he made a 10 percent loss. This means that the loss made on the second car would be

10/100 × 1980 = 0.1 × 1980 = $198

Amount for which he sold the second car would be

1980 - 198 = $1782

Total cost of both cars = 1980 + 1980 = $3960

Total selling price = 2178 + 1782 = $3960

Profit or loss = selling price - cost price. Therefore

Profit or loss = 3960 - 3960 = $0

Step-by-step explanation:

Neither.  He came out even.  The profit made on the first sale was exactly wiped out by the loss on the second sale.

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation: