In poker, there is a 52 card deck with 4 cards each of each of 13 face values. a full house is a hand of 5 cards with 3 of one face value, and 2 of another. what is the probability that a random poker hand is a full house? you can leave your answer in terms of bionomial co-efficients and similar factors, but explain each term.

P(FH) =0.00144

Step-by-step explanation:

The total number of possible poker hands (n) is the combination of 5 out of 52 cards:

In order to get a full house, first pick one out of 13 cards (13 choose 1), then pick 3 out of the 4 cards of the chosen type to form three of a kind (4 choose 3), now pick another card from the remaining 12 different numbers or faces (12 choose 1), then pick 2 out of the 4 suits to form a pair (4 choose 2)

The probability of getting a fullhouse, in binomial coefficients is:

Expanding the coefficients and solving:

hi there!

the answer to this question is d: 35

step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

step-by-step explanation:

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