Find the equation of the line passing through the points (3,-2) and (3, 4). The answer is x = 3. I'm just wondering how my textbook got to this solution.

My work:

y-y1=m(x-x1). m=y2-y1 / x2-x1. y=mx+b

m=4--2 / 3-3 = 6/0 = 0. m=0.

y--2=0(x-3) = y=0-2 y=-2 <<<<
But that's the wrong answer, so I'm very confused.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)

four boxes of pizza

hope this