Find the length of the shorter leg of a right triangle with the longer leg is 9 feet more than the shorter leg the hypotenuse is nine feet less than twice the shorter leg

Length of Shorter leg = 27 feet

Length of Longer leg = 36 feet

Length of Hypotenuse = 45 feet

Step-by-step explanation:

Given:

Let,

    Length of Shorter leg = x,

According to the given condition we have

∴  Length of Longer leg = x + 9 feet

∴  Length of Hypotenuse = 2x - 9 feet

To Find:

Length of Shorter leg = ?

Solution:

Now In Right Angle Triangle, By Pythagoras theorem we have

substituting the given values we get

By using Identity (A ± B)² = A² ± 2AB +B²  we get

Substituting x=27 we get

∴  Length of Longer leg = x + 9 =27 +9 = 36 feet

∴  Length of Hypotenuse = 2x - 9 = 2×27 -9 = 45 feet

answer: im gonna go with milli

step-by-step explanation:

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c