Which polynomial will definitely have nonreal zeros?
hint: use descartes's rule of signs.
x3 − 2x2 − x − 2
x3 − 2x2 + x − 2
x4 + 8x2 + 16
x4 − 8x2 + 16

The best and most correct answer among the choices provided by the question is the second choice. The polynomial that will definitely have non-real zeroes would be x3 − 2x2 + x − 2, and it can be solved using the Descartes's rule of signs. I hope my answer has come to your help. God bless and have a nice day ahead!

It is the top one. the answer is -7. that is smallest