In solving \\(x^{2}=3\\) we obtain

options

\\(â€" 1, 1 \\)

\\(1, - 4\\)

\\(1, - 1\\)

\\(â€" 1, 4 \\)

For this case we must solve the following equation:

So we have to:

Applying square root to both sides of the equation:

Thus, we have two roots:

it would be 6xy and -16xy.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2