Suppose the true average growth μ of one type of plant during a 1-year period is identical to that of a second type, but the variance of growth for the first type is σ2, whereas for the second type the variance is 4σ2. let x1, , xm be m independent growth observations on the first type [so e(xi) = μ, v(xi) = σ2], and let y1, , yn be n independent growth observations on the second type [e(yi) = μ, v(yi) = 4σ2]. (a) show that the estimator mu hat = δx + (1 − δ)y is unbiased for μ (for 0 < δ < 1, the estimator is a weighted average of the two individual sample means). e(mu hat) = e(δx + (1 − δ)y) = e(x) + e(y) = δμ + μ = (b) for fixed m and n, compute v(mu hat).

the final amount you will pay is $68.04.

the tip is determined by the pre-tax amount, so we calculate the tip based on the original bill, not after we've added sales tax.

to find the tip:

we can divide 54.00 by 100 to get 1% of 54. then we multiply that by 18.

54 / 100 = .54

.54 x 18 = 9.72

tip = 9.72$

to find the tax:

we can divide 54.00 by 100 to get 1% of 54. then we can multiply that by 8 to get 8%.

54 / 100 = .54

.54 x 8 = 4.32

tax= 4.32

now we can add the tip and tax to the bill to get our total.

54 + 9.72 + 4.32 = 68.04

total: $68.04

step-by-step explanation:

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

i'm a sophomore in connections, i'd recommend checking on jishka.com they have a large range of questions and answers from our school.