Can someone plz help me

Your table might look something like this:

The dads steps:

3

6

9

12

15

18

Sons steps:

5

10

15

20

25

30

You can notice the pattern. If dad walks 3 steps, son walks 5. If dad walks another 3, son walks another 5. And so on. This means dad walks 12 steps when the sin walks 20 steps.

Step-by-step explanation:

The ratio is 3:5. This means dad wlaks 3 steps so son must walk 5 steps basically. So You can now create the table. Y I just have to multiply or divide each side ( of the colon:) so. Whatever you do to one side, you do to the other side. If you x3 on one side, you do it to other. Same goes for division. In the 'table' I did above, I x2 to get 6 and 10. Then I took the 3 and the 5 again and timsed those by 3. You can also change the 6 and the 10. So:

3:5

Then x2

6:10

Then I take the top layer (you can either choose to change the top layer, or layer above as long as you do the same thing to each side. Remember, only x and ÷. No + or-.) and I x3

9:15

Then I could take 9 and 15 and x5

45:75

It's crazy that all these. Ratios mena the same thing! 45 steps from dad would take the son 75 steps. You can also divide the last ratio of 45:75 to find the one you started with, 3:5.

So you get the idea.

It is probably best to do what I did in the table in the answer part because I did a pattern. Take the top layer, and x2, then x3, then x4, ect. Rather then doing random things.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!