Astandard deck of cards consists of four suits (clubs, diamonds, hearts, and spades), with each suit containing 13 cards (ace, two through ten, jack, queen, and king) for a total of 52 cards in all. how many 7-card hands will consist of exactly 2 hearts and 3 clubs?

1,977,300

Step-by-step explanation:

Given,

Total cards = 52,

In which,

Clubs = 13, diamond = 13, heart = 13, spades = 13,

Ways of choosing exactly 2 hearts =

Ways of choosing exactly 3 clubs =

So, the total possible ways of selecting 7 cards that contains exactly 2 hearts and 3 clubs

= Choosing exactly 2 hearts × Choosing exactly 3 clubs × choosing any 2 cards except hearts and clubs

= 1,977,300

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

21

jk it's 20

step-by-step explanation: