In four hours, a hiker in a canyon goes from 892 ft to 256 ft above the canyon floor. find the hiker’s vertical speed. a. 287 ft/h b. –287 ft/h c. –159 ft/h d. 159 ft/h

C is the correct option

Step-by-step explanation:

In four hours, a hiker in a canyon goes from 892 ft to 256 ft above the canyon floor.

From the above information,

Total distance travelled by the hiker in moving from 892 ft to 256 ft above the Canyon is 256 - 892 = -636 ft

Speed = distance travelled/time

The hiker’s vertical speed is total distance travelled vertically divided by the time it takes to travel the vertical distance. It becomes

-636/4 = –159 ft/h

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