25 pts and athat there are two types of tickets to a show: advance and same-day. advance tickets cost $35 and same-day tickets cost $15. for one performance, there were 65 tickets sold in all, and the total amount paid for them was $1675. how many tickets of each type were sold?

The answer would be

Advance tickets($35)- 35 tickets sold

Same-day tickets($15)-30 tickets sold

Step-by-step explanation:

35×35=1,225

15×30=450

1225+450= $1675

there are no short passages to look at

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b