Acommunity bird-watching society makes and sells simple bird feeders to raise money for its conservation activities. the materials for each feeder cost $6, and the society sells an average of 30 per week at a price of $10 each. the society has been considering raising the price, so it conducts a survey and finds that for every dollar increase, it loses 3 sales per week. a) find a function that models weekly profit in terms of price per feeder. b) what price should the society charge for each feeder to maximize profits? what is the maximum weekly profit?

The required function is:

The price for each feeder to maximize profit should be $13.

The maximum weekly profit is $147

Step-by-step explanation:

Consider the provided information.

Part (A)

The materials for each feeder cost $6, and the society sells an average of 30 per week at a price of $10 each.

Let x be the price per feeder.

Profit = Revenue - cost

So the profit per feeder is

If we increase then for every dollar increase, it loses 3 sales per week.

This can be written as:

Where x-10 represents the increase in price and 3  represents the decrease in sales per week.

Thus the profit will be:

Hence, the required function is:

Part (B) What price should the society charge for each feeder to maximize profits? What is the maximum weekly profit?

The above function is a downward parabola so the maximum will occur at vertex.

The x coordinate of the vertex of parabola is:

Substitute a=-3, b=78 and c=-360 in above.

Hence, the price for each feeder to maximize profit should be $13.

Now substitute the value of x in

Hence, the maximum weekly profit is $147

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05