Prove identity: tanx-1/tanx+1= 1-cotx/1+cotx

to answer the question above, take the LHS. 
[(tan x - 1) / (tan x + 1)] = 

Remember that tan x = 1 / cot x. 
{[(1 / cot x) - 1] / [(1 / cot x) + 1]} = 

The LCD is cot x. Multiply as needed to get the common denominator for all terms. 
{[(1 / cot x) - 1(cot x / cot x)] / [(1 / cot x) + 1(cot x / cot x)]} = 
{[(1 / cot x) - (cot x / cot x)] / [(1 / cot x) + (cot x / cot x)]} = 

Then Simplify. 
[(1 - cot x) / cot x] / [(1 + cot x) / cot x] = 

Remember that (a / b) / (c / d) = (a / b) * (d / c). 
[(1 - cot x) / cot x] * [cot x / (1 + cot x)] = 
[(1 - cot x) / (1 + cot x )] = 
RHS
The answer is
 [(tan x - 1) / (tan x + 1)] = [(1 - cot x) / (1 + cot x )] 

What is the inequality?

Horatian satire is more witty and tolerant.named after the roman satirist horacegently criticizes human nature and human follyjuvenalian satire is more angry and personal, attempting to produce anger in the reader.named after roman satirist juvenalattacks human vice-indignant