Find the value of x so that the function has the given value

1. h(x) = -7x; h(x)=63

2. m(x) = 4x + 15; m(x)=7

3. q(x) = 1/2x - 3; q(x) = -4

explain your work

Step-by-step explanation:

We are looking for the value of x so that the function has the given value in the following:

1) h(x) = -7x; h(x)=63

From the function given above,

If h(x) = 63, then,

h(x) = 63 = -7x

-7x = 63

Dividing the left hand side and right hand side of the equation by -7, it becomes

-7x/-7 = 63/-7

x = - 9

2) m(x) = 4x + 15; m(x)=7

From the function given above,

If m(x) = 7, then,

m(x) = 7 = 4x + 15

7 = 4x + 15

4x = 15 - 7 = 8

Dividing the left hand side and right hand side of the equation by 4, it becomes

4x/4 = 8/4

x = 2

3) q(x) = 1/2x - 3; q(x) = -4

From the function given above,

If q(x) = - 4, then,

q(x) = - 4 = 1/(2x - 3) =

Cross multiplying,

-4(2x-3) = 1

-8x +12 = 1

Collecting like terms,

-8x = 1 - 12

-8x = -11

Dividing the left hand side and right hand side of the equation by -8, it becomes

-8x/8 = -11/-8

x = 11/8

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )