J(–6, 2) and k(3, 2) are the endpoints of the base of an isosceles triangle. give the x-coordinate of the third vertex.

Step-by-step explanation:

If you plot J and K in a coordinate plane, you see that the line formed is a perfectly horizontal line through y = 2.  In order for this triangle to be an isosceles, the third x-coordinate would have to be located midway through the x-coordinates of the base.  The midpoint between the x-coordinates is found by adding the 2 x-coordinates and dividing the sum by 2.  -6+\3 = -3 and -3/2 = -3/2.  So the x-coordinate is -3.2 or -1.5

  -3/2

Step-by-step explanation:

The third vertex of an isosceles triangle is on the perpendicular bisector of the base. Here, the base is on the horizontal line y=2, so the perpendicular bisector will be on the vertical line with the x-value the same as the midpoint of the base.

That x-value is (-6 +3)/2 = -3/2.

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.